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Question

The function f(x)=⎪ ⎪ ⎪⎪ ⎪ ⎪sin(3x)ln(1+3x)(tan1x)2(e(53x)1)a,x0x=0 is continuous at x=0, then value of x is

A
0
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B
35
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C
2
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D
53
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Solution

The correct option is B 35
f(x)=⎪ ⎪ ⎪ ⎪⎪ ⎪ ⎪ ⎪sin(x13)ln(1+3x)(tan1x)(e53x1);x0a;x=0ltx0sin(x13)ln(1+3x)(tan1x)2(x)2(x)(e53x1)5x135x13ltx0sin(x13)ln(1+3x)(x)2(5x13)ltx0sin(x13)ln(1+3x)(3x)x13(3x)(5x)=35a=35=f(0)Hence,theoptionBisthecorrectanswer.

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