Question

The function $f\left(x\right)$ $=\frac{x}{e^2-1}+\frac{x}{2}+1$ is

• A. $Even$
• B. $Odd$
• C. $Both$
• D. $Neither$

Answer 1

Answer: (D)

$Neither$

$f\left(x\right)=\frac{x}{e^2-1}+\frac{x}{2}+1$

and

$f(-x)=\frac{-x}{e^2-1}+\frac{-x}{2}+1$

We can see that

$f\left(x\right)\ne f(-x)f(-x)\ne -f\left(x\right)$

it is neither even nor odd function