The function f(x)=2ln(x−2)−x2+4x+1 increases in the interval-
A
(1,2)
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B
(2,3)
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C
(−∞,−1)
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D
(2,4)
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Solution
The correct option is B(2,3) f′(x)>0 for monotonically increasing function. Hence 2x−2−2x+4>0 Or 2x−2>2x−4 Or 1x−2>x−2 Or (x−2)2<1 −1<x−2<1 Or 1<x<3 Hence xϵ(1,3) However x−2>0 since input of logarithmic function cannot be negative. (x−2)>0 or x>2 Hence xϵ(2,3).