The function f(x)= $2 x^{3} - 9 x^{2} + 12 x + 4$ is decreasing in the interval(s)

(- \infty, 1)

and

(2, \infty)

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(- \infty, 1)

only

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(1, 2)

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(2, \infty)

only

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Solution

The correct option is C (1, 2)
(f(x) = $2 x^{3} - 9 x^{2} + 12 x + 4$
f'(x) = $6 x^{2} - 18 x + 12 = 6 (x^{2} - 3 x + 2) = 6 (x - 1) (x - 2) > 0 f^{'} (x) > 0 i n (- \infty, - 1) \cup (2, \infty) f^{'} (x) < 0 i n (1, 2)$

Suggest Corrections

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