The functionf(x)=log(1+ax)−log(1−bx)x is not defined at x=0. The value of which should be assigned to f at x=0, is
A
a−b
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B
a+b
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C
loga+logb
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D
None of these
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Solution
The correct option is Ba+b For f(x) to be continuous, we must have f(0)=limx→0f(x) =limx→0log(1+ax)−log(1−bx)x=limx→0alog(1+ax)ax+blog(1−bx)−bx =a.1+b.1[using=limx→0log(1+x)x=1]=a+b