1
You visited us
1
times! Enjoying our articles?
Unlock Full Access!
Byju's Answer
Standard XII
Mathematics
Even Function
The function ...
Question
The function
f
(
x
)
=
1
x
4
+
x
2
+
1
is
A
Discontinuous at
x
=
0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
Discontinuous at
x
=
1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
Discontinuous at
x
=
−
1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
Continuous at every where
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution
The correct option is
D
Continuous at every where
f
(
x
)
=
1
x
4
+
x
2
+
1
⇒
f
(
x
)
=
1
(
x
2
+
1
2
)
2
+
3
4
Now,
(
x
2
+
1
2
)
2
+
3
4
≥
1
∀
x
∈
R
Hence,
f
(
x
)
is continuous
∀
x
∈
R
Suggest Corrections
0
Similar questions
Q.
Integrate the following function: f(x)=
1
x
4
+
x
2
+
1
Q.
The function
f
(
x
)
=
{
x
4
+
x
2
−
x
+
2
f
o
r
x
≤
1
3
x
3
−
x
2
+
x
f
o
r
x
>
1
is
Q.
Find the range of
f
(
x
)
=
sin
(
π
[
x
2
+
1
]
)
x
4
+
1
where
[
.
]
is greatest integer function
Q.
* If
f
(
x
)
=
1
+
x
2
and
f
[
g
(
x
)
]
=
1
+
x
2
−
2
x
3
+
x
4
, then determine the function g(x) along with range.
Q.
The range of
f
(
x
)
=
sin
π
[
x
2
−
1
]
x
4
+
1
is
View More
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
Explore more
Even Function
Standard XII Mathematics
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
AI Tutor
Textbooks
Question Papers
Install app