The function f(x)=log(1+ax)−log(1−bx)x is not defined at x = 0. The value which should be assigned to f at x = 0 so that it is continuos at x = 0, is
A
a - b
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B
a + b
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C
log a + log b
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D
log a - log b
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Solution
The correct option is B a + b Since limit of a function is a + b as x → 0. {We can apply L'Hospital rule to find the limit easily.} Therefore it to be continuous at x= 0, its value must be (a + b) at x = 0 ⇒ f(0) = a + b