The function f(x)=log(1+ax)−log(1−bx)x is not defined at x = 0. The value which should be assigned to f at x =0 so that it is continuos at x = 0, is
A
a - b
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
a + b
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
log a + log b
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
log a - log b
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is B a + b Since limit of a function is a + b as x→0,therefore to be continuous at a function, its value must be a + b at x = 0 ⇒ f(0) = a + b