The function f(x)=∣∣x2−3x+2∣∣+cos|x| is not differentiable at x=
A
-1
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B
0
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C
1
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D
2
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Solution
The correct options are A 1 D 2 f(x)=∣∣x2−3x+2∣∣+cos|x|=|(x−1)(x−2)|+cos|x| cos|x| is differentiable for all x as cos(|x|)=cosx∀x∈R But |(x−1)(x−2)| is not differentiable at x=1,2 Hence F(x) is not differentiable at x=1,2