Question

The function $f\left(x\right)=log(x+\sqrt{x^2+1})$, is

• A. An even function
• B. An odd function
• C. A Periodic function
• D. Neither an even nor odd function

Answer 1

The correct option is B

An odd function

$f\left(x\right)=log(x+\sqrt{x^2+1})$

and $f(-x)=-log(x+\sqrt{x^2+1})$=$-f\left(x\right)$

$f\left(x\right)$ is odd function.