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First Principle of Differentiation

The function ...

Question

$The function f (x) = sec x is continuous for all x \in R .$

A

True

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B

False

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Solution

The correct option is B False

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Similar questions

The function f (x) = sec x is continuous for all x \in R .

f : R \to R

be a continuous function satisfying

f (0) = 1

f (2 x) - f (x) = x

x \in R .

f (2020)

f (x) = ⎧ ⎪ ⎨ ⎪ ⎩ \begin{matrix} lim n \to \infty \frac{e^{x^{2}} - 1 + [(a + b) x - (a - b)] x^{2 n}}{x^{2 n + 1} + cos x - 1}, & x \in R - {0} k, & x = 0 \end{matrix}

f (x)

is continuous for all

x \in R

f : R \to R

be a continuous function such that

f (x) + f (x + 1) = 2,

x \in R .

I_{1} = \int_{0}^{8} f (x) d x

I_{2} = \int_{- 1}^{3} f (x) d x

then the value of

I_{1} + 2 I_{2}

f (x + y) = f (x) + f (y)

for all x and y. If the function

f (x)

is continuous at

x = 0

f (x)

is continuous for all x.

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