The function f x - -log x 2 x is defined for x-

The correct option is C ( 1 , ∞ ) √(log_x^2x) is defined when x^2 gt;0 and x^2≠ 1 and x gt;0 ⇒ (0,∞) {1}=(1,∞) ...

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Standard XII

Mathematics

Definition of Functions

The function ...

Question

The function $f (x) = \sqrt{{log}_{x^{2}} x}$ is defined for $x$ :

(- \infty, 0)

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(0, 1)

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(1, \infty)

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(0, \infty)

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Solution

The correct option is C $(1, \infty)$
$\sqrt{{log}_{x^{2}} x}$ is defined when $x^{2} > 0$ and $x^{2} \neq 1$ and $x > 0$
$\Rightarrow (0, \infty) - {1} = (1, \infty)$

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The function f(x)=√logx2x is defined for x:

The correct option is C (1,∞)√logx2x is defined when x2>0 and x2≠1 and x>0⇒(0,∞)−{1}=(1,∞)

The function $f (x) = \sqrt{{log}_{x^{2}} x}$ is defined for $x$ :

The correct option is C $(1, \infty)$
$\sqrt{{log}_{x^{2}} x}$ is defined when $x^{2} > 0$ and $x^{2} \neq 1$ and $x > 0$
$\Rightarrow (0, \infty) - {1} = (1, \infty)$