The function f x - -log x 2 x is defined for x-

The correct option is C ( 1 , ∞ ) √(log_x^2x) is defined when x^2 gt;0 and x^2≠ 1 and x gt;0 ⇒ (0,∞) {1}=(1,∞) ...

197

You visited us 197 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Mathematics

Definition of Functions

The function ...

Question

The function $f (x) = \sqrt{{log}_{x^{2}} x}$ is defined for $x$ :

(- \infty, 0)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(0, 1)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(1, \infty)

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

(0, \infty)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $(1, \infty)$
$\sqrt{{log}_{x^{2}} x}$ is defined when $x^{2} > 0$ and $x^{2} \neq 1$ and $x > 0$
$\Rightarrow (0, \infty) - {1} = (1, \infty)$

Suggest Corrections

Similar questions

Q. The function

f (x) = \sqrt{{log}_{x}^{2} (x)}

is defined for x belonging to

Q. Let

f : [0, 1] \to [0, 1]

be defined by

f (x) = \frac{1 - x}{1 + x}, 0 \leq x \leq 1

and let

g : [0, 1] \to [0, 1]

be defined by

g (x) = 4 x (1 - x), 0 \leq x \leq 1

. Determine the composition functions fog(1)

Q. The function defined by

f (x) = max {x^{2}, (x - 1)^{2}, 2 x (1 - x)}

for

0 < x < 1

Let f(x) be a function defined on [0, 1] such that $f (x) = {\begin{matrix} x, & i f x ϵ Q 1 - x, & i f x / ϵ Q \end{matrix}$
Then, for all $x ϵ [0, 1], f (f (x)) =$

Q. Function

f (x) = \frac{x}{1 + x}

defined from

[0, \infty) \to [0, \infty), f (x)

is:

Join BYJU'S Learning Program

The function f(x)=√logx2x is defined for x:

The correct option is C (1,∞)√logx2x is defined when x2>0 and x2≠1 and x>0⇒(0,∞)−{1}=(1,∞)

The function $f (x) = \sqrt{{log}_{x^{2}} x}$ is defined for $x$ :

The correct option is C $(1, \infty)$
$\sqrt{{log}_{x^{2}} x}$ is defined when $x^{2} > 0$ and $x^{2} \neq 1$ and $x > 0$
$\Rightarrow (0, \infty) - {1} = (1, \infty)$