The function f x -tan x is discontinuous at x -A- NB- -4C- n-2D- T

The correct option is D πThe function f(x) = tan x is undefined at x=π/2. Also, lim_x →π/2 tan x=∞ Since the limit of the function doesn't exist finitely at x= ...

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Standard XI

Mathematics

Graphical Interpretation of Continuity

The function ...

Question

The function f(x)=tan x is discontinuous at x = .

0.0

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\frac{π}{4}

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\frac{π}{2}

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π

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Solution

The correct option is D $π$
The function $f (x) = t a n x$ is undefined at $x = \frac{π}{2}$ .
Also, $lim x \to \frac{π}{2} t a n x = \infty$

Since the limit of the function doesn't exist finitely at $x = \frac{π}{2}$ , it is discontinuous at that point.

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Similar questions

Q. Among the given options, the function

f (x) = t a n x

is discontinuous at .

Q. Function

f (x) = tan x

is discontinuous at-

Q. If

f (x) = {\begin{matrix} x s i n x, & w h e n 0 < x \leq \frac{π}{2} \frac{π}{2} s i n (π + x), & w h e n \frac{π}{2} < x < π \end{matrix}, t h e n

Q. If

f (x) - {\begin{matrix} x s i n x, & w h e n 0 < x \leq \frac{π}{2} \frac{π}{2} s i n (π + x), & w h e n \frac{π}{2} < x < π \end{matrix}

, then

If the function $f (x) = {\begin{matrix} \frac{k c o s x}{π - 2 x}, i f x \neq \frac{π}{2} 3, i f x = \frac{π}{2} \end{matrix}$

is continues at $x = \frac{π}{2}$

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The function f(x)=tan x is discontinuous at x = .

The correct option is D πThe function f(x)=tan x is undefined at x=π2. Also, limx→π2tan x=∞ Since the limit of the function doesn't exist finitely at x=π2, it is discontinuous at that point.

The correct option is D $π$
The function $f (x) = t a n x$ is undefined at $x = \frac{π}{2}$ .
Also, $lim x \to \frac{π}{2} t a n x = \infty$

Since the limit of the function doesn't exist finitely at $x = \frac{π}{2}$ , it is discontinuous at that point.