The function f(x)=x1/x has stationary point at
Atstationarypointsf′(x)=0Nowy=x1/x∴logy=(1x)⋅logx(1y)⋅(dydx)=(1/x⋅x−logx⋅1x2)as(dydx)=0∴0=(1−logxx2)orlogx=1∴x=e
If f(x) =(1+x)1x−ex then