The function y=|2sinx| is continuous for any x but it is not differentiable at
A
Only x=0
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B
Only x=π
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C
Only x=π2
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D
x=kπ (k is an integer)
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Solution
The correct option is Dx=kπ (k is an integer) The graph of y=|2sinx| is given below: It can be easily seen from the graph of f(x)=|2sinx|, it is continuous everywhere but not differentiable at integer multiples of π.