The function $y = {(x^{2} + 1)}^{50}$ is differentiated 70 times to get $y_{70} (x)$ . Then $y_{70} (x)$ is a polynomial of degree is equal to

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Solution

Note that y is a polynomial of degree 100 and differentiation once reduce the degree by one. Hence if y is differentiated 70 times it will result in a polynomial of degree 30.

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Similar questions

y = (x^{2} + 1)^{80}

50

f

f (x) = x^{2} + \int_{0}^{x} e^{- t} f (x - t) d t

f (x^{2})

f (x) = x^{2} + 7 x + 4

f^{'} (2) = 11

y^{2} = p (x)

2 \frac{d}{d x}

[y^{3} \frac{d^{2} y}{d x^{2}}]

Consider the figure:

If $∠$ A = $50^{\circ}$ , $∠$ B = $70^{\circ}$ and x = 2y, then x+y is equal to (in degrees)

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