Question

The fundamental component of output voltage (in V) for half wave bridge inverter operating at $V_s=100V$ and switching frequency of 50 Hz will be

Answer 1

The fourier analysis of half wave inverter will be
$V_0=\sum _{n=1,3,\mathrm{5...}}^{\infty }\frac{2V_s}{n\pi }sin\left(n\omega t\right)$

By putting, n = 1
$V_0=\frac{2\times 100}{\pi }sin(1\times 2\times \pi \times 50\times t)$

$=\frac{200}{\pi }sin100\pi tV$