The fundamental frequency in a stretched string is $100 H z$ . To double the frequency, the tension in it must be changed to

T_{2} = 2 T_{1}

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T_{2} = 4 T_{1}

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T_{2} = T_{1}

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T_{2} = \frac{T_{1}}{4}

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Solution

The correct option is B $T_{2} = 4 T_{1}$
Fundamental frequency $ν \propto \sqrt{T}$ .
So, $\frac{ν}{ν^{'}} = \sqrt{\frac{T}{T^{'}}} \Rightarrow \frac{T}{T^{'}} = {(\frac{ν}{ν^{'}})}^{2} = \frac{1}{4}$
$\Rightarrow T^{'} = 4 T$ .

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The fundamental frequency in a stretched string is 100 Hz. To double the frequency, the tension in it must be changed to

The correct option is B T2=4T1Fundamental frequency ν∝√T. So, νν′=√TT′⇒TT′=(νν′)2=14 ⇒T′=4T.

The fundamental frequency in a stretched string is $100 H z$ . To double the frequency, the tension in it must be changed to

The correct option is B $T_{2} = 4 T_{1}$
Fundamental frequency $ν \propto \sqrt{T}$ .
So, $\frac{ν}{ν^{'}} = \sqrt{\frac{T}{T^{'}}} \Rightarrow \frac{T}{T^{'}} = {(\frac{ν}{ν^{'}})}^{2} = \frac{1}{4}$
$\Rightarrow T^{'} = 4 T$ .