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Wave Equation

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Question

The fundamental frequency of a closed organ pipe is 220 Hz. The length of this pipe in meters is $392 \times 10^{- x}$ Find x.

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Solution

Fundamental frequency $f$ of a closed organ pipe is given by ,
$f = v / 4 l$ ,
where $v = 344 m / s$ velocity of sound in air ,
$l =$ length of pipe ,
given $f = 220 H z$ ,
therefore ,
$l = v / 4 f = 344 / (4 \times 220) = 0.390 m$

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