The fundamental frequency of an open pipe is $n$ . If the pipe is vertically immersed in water up to half the length of the pipe, then the fundamental frequency of the air column in the remaining pipe will be

(1 / 2) n

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(3 / 4) n

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n

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2 n

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Solution

The correct option is B $n$
Fundamental frequency of the open pipe is $ν_{0 o} = \frac{v}{2 l} = n$
The fundamental frequency of the closed pipe with length $(l / 2)$ can be given by $ν_{0 c} = \frac{v}{4 \frac{l}{2}} = \frac{v}{2 l} = n$

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The fundamental frequency of an open pipe is n. If the pipe is vertically immersed in water up to half the length of the pipe, then the fundamental frequency of the air column in the remaining pipe will be

The correct option is B nFundamental frequency of the open pipe is ν0o=v2l=nThe fundamental frequency of the closed pipe with length (l/2) can be given by ν0c=v4l2=v2l=n

The fundamental frequency of an open pipe is $n$ . If the pipe is vertically immersed in water up to half the length of the pipe, then the fundamental frequency of the air column in the remaining pipe will be

The correct option is B $n$
Fundamental frequency of the open pipe is $ν_{0 o} = \frac{v}{2 l} = n$
The fundamental frequency of the closed pipe with length $(l / 2)$ can be given by $ν_{0 c} = \frac{v}{4 \frac{l}{2}} = \frac{v}{2 l} = n$