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Potassium Dichromate

The fusion of...

Question

The fusion of chromite ore $(F e C r_{2} O_{4})$ with $N a_{2} C O_{3}$ in air gives a yellow solution upon addition of water. Subsequent treatment with $H_{2} S O_{4}$ produces an orange solution. The yellow and orange colours, respectively, are due to the formation of:

N a_{2} C r O_{4}

and

N a_{2} C r_{2} O_{7}

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C r (O H)_{3}

and

N a_{2} C r_{2} O_{7}

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C r_{2} (C O_{3})_{3}

and

F e_{2} (S O_{4})_{3}

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C r (O H)_{3}

and

N a_{2} C r O_{4}

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Solution

The correct option is A $N a_{2} C r O_{4}$ and $N a_{2} C r_{2} O_{7}$
$4 F e C r_{2} O_{4} + 8 N a_{2} C O_{3} + 7 O_{2} \to 8 N a_{2} C r O_{4} + 2 F e O_{3} + 8 C O_{2}$

$N a_{2} C r O_{4} + H_{2} S O_{4} \to N a_{2} C r_{2} O_{7} + N a_{2} S O_{4} + H_{2} O$

Yellow -----> $N a_{2} C r O_{4}$

Orange ----> $N a_{2} C r_{2} O_{7}$

Suggest Corrections

Similar questions

F e C r_{2} O_{4}

N a_{2} C r O_{4}

N a_{2} C r_{2} O_{7}

F e C r_{2} O_{4} + N a O H + a i r ⟶ (A) + F e_{2} O_{3}

(A) + (B) ⟶ N a_{2} C r_{2} O_{7}

N a_{2} C r_{2} O_{7} + X △ ⟶ C r_{2} O_{3}

C r_{2} O_{3} + Y △ ⟶ C r

N a_{2} C r O_{4}

C O_{2}

F e C r_{2} O_{4} + N a O H + a i r \to (A) + F e_{2} O_{3}

(A) + (B) \to N a_{2} C r_{2} 07

N a_{2} C r_{2} O_{7} + X Δ - \to C r_{2} O_{3}

C r_{2} O_{3} + Y Δ - \to C r

F e C r_{2} O_{4}

N a_{2} C O_{3}

7 O_{2}

\to

N a_{2} C r O_{4}

H_{2} S O_{4}

\to

N a_{2} C r_{2} O_{7}

2 K C l

\to

4^{t h}

K C l

H_{2} S O_{4}

H_{2} S O_{4}

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