The G.C.D of $x^{2} - 3 x + 2$ and $x^{2} - 4 x + 4$

x - 2

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(x - 2) (x - 1)

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(x - 2)^{2}

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(x - 2)^{3} (x - 1)

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Solution

The correct option is B $x - 2$
$x^{3} - 3 x + 2 = (x - 2) (x - 1)$

$x^{2} - 4 x + 4 = (x - 2) (x - 2)$

GCD of $x^{3} - 3 x + 2$ and $x^{2} - 4 x + 4$ is $(x - 2)$

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