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Question

The galvanometer deflection, when key K1 is closed but K2 is open, equals θ0 (see figure). On closing K2 also and adjusting R2to5Ω , the deflection in galvanometer becomes θ05 .The resistance of the galvanometer is, then, given by [Neglect the internal resistance of battery]:
1332841_3addb52f0b5f4658980b46d9e4df0a3b.PNG

A
12Ω
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B
25Ω
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C
5Ω
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D
22Ω
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Solution

The correct option is C 22Ω
case I ig=E220+Rg=Cθ0 ..(i)
caseII ig=(E220+5Rg5+Rg)×5(Rg+5)=Cθ05...(ii)
5E225Rg+1100=Cθ05 ..(ii)
E220+Rg=Cθ
...(i)
225Rg+11001100+5R0=5
5500+25Rg=225Rg=1100
200Rg=4400
Rg=22Ω
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