Question

The garbage collector collects $5.8\times {10}^{10}$ lb of garbage in Day 1 and $9.5\times {10}^{12}$ lb in Day 2. What is the total amount of garbage that he collects in two days?

• A. $955.8\times {10}^{12}$ lb
• B. $9.558\times {10}^{12}$ lb
• C. $9.558\times {10}^{10}$ lb
• D. $95.58\times {10}^8$ lb

Answer 1

The correct option is B $9.558\times {10}^{12}$ lb

Garbage collected in Day 1
= 5.8$\times {10}^{10}$ lb

Garbage collected in Day 2
= 9.5$\times {10}^{12}$ lb

Garbage collected in two days

= Garbage collected on Day 1 + Garbage collected on Day 2

= $5.8\times {10}^{10}+9.5\times {10}^{12}$

To make the exponents of both the values same

= $5.8\times {10}^{10}+950\times {10}^{10}$

= (5.8 + 950)$\times {10}^{10}$

= 955.8$\times {10}^{10}$

= 9.558$\times {10}^{12}$ lb

Therefore, the total amount of garbage collected in 2 days is $9.558\times {10}^{12}$ lb.