The gas A 2 in the left flask allowed to react with gas B 2 present in right flask as -A 2- B 2- 2 AB g - K c -4 at 27- CWhat is the concentration of AB when equillibrium is established-A- 1-33 MB- 2-66 MC- 0-66 MD- 0-33 M

The correct option is C 0.66M A_2+B_2⇌ 1AB t=0 2 4 0 at equi. 2 x 4 x 2x 4=4x^2/(2 x)(4 x) ⇒ x^2=8 6x+x^2 ⇒ x=8/6=1.33 ⇒ ...

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Byju's Answer

Standard XII

Chemistry

Concentration Terms - An Introduction (w/w etc)

The gas A 2 i...

Question

The gas $A_{2}$ in the left flask allowed to react with gas $B_{2}$ present in right flask as ?

$A_{2} + B_{2} ⇌ 2 A B (g); K_{c} = 4 a t 27^{\circ} C$
What is the concentration of AB when equillibrium is established-

1.33M

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2.66M

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0.66M

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0.33M

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Solution

The correct option is C
0.66M

$A_{2} + B_{2} ⇌ 1 A B t = 0240 a t e q u i . 2 - x 4 - x 2 x 4 = \frac{4 x^{2}}{(2 - x) (4 - x)} \Rightarrow x^{2} = 8 - 6 x + x^{2} \Rightarrow x = 8 / 6 = 1.33 \Rightarrow [A B] = \frac{2 x}{4} = \frac{x}{2} = 0.665$

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Similar questions

Q.
2mol of

A_{2}

gas in one flask (1 lit volume) is allowed to react with 4 mol of

B_{2}

gas presence in another flask (3 lit volume) as

A_{2} (g) + B_{2} (g) ⇌ 2 A B (g); K_{c} = 4 a t 27^{o} C .

What is the concentration of AB when equilibrium is established?

Q. The gas

A_{2}

in the left flask allowed to react with gas

B_{2}

present in right flask as

A_{2} (g) + B_{2} (g) ⇌ 2 {AB(g) ; K}_{C} = 4 at 27^{\circ} C

What is the concentration of

A B

when equilibrium is established?

Q. The gas

A_{2}

in the left flask allowed to react with gas

B_{2}

present in right flask at

A_{2} (g) + B_{2} (g) ⇌ 2 A B (g), K_{C} = 4

27^{\circ} C

. What is the concentration of

A B

when equilibrium is established?

Q. The gas

A_{2}

in the left flask is allowed to react with gas

B_{2}

presence in right flask as

A_{2} (g) + B_{2} (g) ⇌ 2 A B (g); K_{c} = 4

27^{o} C

. What is the concentration of

A B

when equilibrium is established?

The gas

A_{2}

in the left flask allowed to react with gas

B_{2}

present in the right flask as

A_{2} (g) + B_{2} (g) ⇌ 2 A B (g); K_{c} = 4

27^{o} C

. What is the concentration of

A B

when equilibrium is established?

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The gas A2 in the left flask allowed to react with gas B2 present in right flask as ? A2+B2⇌2AB(g); Kc=4 at 27∘C What is the concentration of AB when equillibrium is established-

The correct option is C 0.66M A2+B2⇌1ABt=0 2 4 0at equi. 2−x 4−x 2x4=4x2(2−x)(4−x)⇒x2=8−6x+x2⇒x=8/6=1.33⇒[AB]=2x4=x2=0.665

The gas $A_{2}$ in the left flask allowed to react with gas $B_{2}$ present in right flask as ?

$A_{2} + B_{2} ⇌ 2 A B (g); K_{c} = 4 a t 27^{\circ} C$
What is the concentration of AB when equillibrium is established-

The correct option is C
0.66M

$A_{2} + B_{2} ⇌ 1 A B t = 0240 a t e q u i . 2 - x 4 - x 2 x 4 = \frac{4 x^{2}}{(2 - x) (4 - x)} \Rightarrow x^{2} = 8 - 6 x + x^{2} \Rightarrow x = 8 / 6 = 1.33 \Rightarrow [A B] = \frac{2 x}{4} = \frac{x}{2} = 0.665$