The gas A2 in the left flask allowed to react with gas B2 present in right flask at A2g - B2g - 2ABg- KC - 4 at 27-C- What is the concentration of AB when equilibrium is established-

The correct option is B 0.66 M A _ 2 + B _ 2 ⇌ 2AB K _ C =4 #160; #160; #160; #160; #160; #160; #160; #160; #160; # ...

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Byju's Answer

Standard XII

Chemistry

Characteristics of Equilibrium Constant

The gas A2 ...

Question

The gas $A_{2}$ in the left flask allowed to react with gas $B_{2}$ present in right flask at $A_{2} (g) + B_{2} (g) ⇌ 2 A B (g), K_{C} = 4$ at $27^{\circ} C$ . What is the concentration of $A B$ when equilibrium is established?

1.33 M

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0.66 M

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0.33 M

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2.66 M

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Solution

The correct option is B $0.66 M$

$A_{2} + B_{2} ⇌ 2 A B K_{C} = 4$

$A_{2} + B_{2} ⇌ 2 A B$
$t = 0$ $2$ $4$ $0$
$t = t_{e q}$ $2 - x$ $4 - x$ $2 x$

Total volume $= 1 + 3 = 4$ lit

$[A B] = \frac{2 x}{4} = x / 2$

$[B_{2}] = \frac{4 - x}{4}$

$[A_{2}] = \frac{2 - x}{4}$

$K_{C} = \frac{{(x / 2)}^{2}}{(\frac{4 - x}{4}) (\frac{2 - x}{4})} \Rightarrow \frac{{4 x}^{2}}{(4 - x) (2 - x)} = 4$

$x^{2} = (4 - x) (2 - x)$

$x^{2} = x^{2} - 6 x + 8$

$6 x = 8$

$x = 4 / 3$

concentration of $A B$ is $x / 2 = 2 / 3 = 0.66 M$
Hence, the correct option is B.

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Similar questions

Q. The gas

A_{2}

in the left flask is allowed to react with gas

B_{2}

presence in right flask as

A_{2} (g) + B_{2} (g) ⇌ 2 A B (g); K_{c} = 4

27^{o} C

. What is the concentration of

A B

when equilibrium is established?

Q. The gas

A_{2}

in the left flask allowed to react with gas

B_{2}

present in right flask as

A_{2} (g) + B_{2} (g) ⇌ 2 {AB(g) ; K}_{C} = 4 at 27^{\circ} C

What is the concentration of

A B

when equilibrium is established?

The gas $A_{2}$ in the left flask allowed to react with gas $B_{2}$ present in right flask as ?

$A_{2} + B_{2} ⇌ 2 A B (g); K_{c} = 4 a t 27^{\circ} C$
What is the concentration of AB when equillibrium is established-

Q.
2mol of

A_{2}

gas in one flask (1 lit volume) is allowed to react with 4 mol of

B_{2}

gas presence in another flask (3 lit volume) as

A_{2} (g) + B_{2} (g) ⇌ 2 A B (g); K_{c} = 4 a t 27^{o} C .

What is the concentration of AB when equilibrium is established?

Q. The gas

A_{2}

in the left flask allowed to react with gas

B_{2}

present in right flask as

A_{2} (g) + B_{2} (g) ⇌ 2 A B (g); K_{c} = 4

27^{\circ}

What is the concentration of

A B

when equilibrium is established ?

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The gas A2 in the left flask allowed to react with gas B2 present in right flask at A2(g)+B2(g)⇌2AB(g),KC=4 at 27∘C. What is the concentration of AB when equilibrium is established?

The correct option is B 0.66 MA2+B2⇌2ABKC=4 A2+B2⇌2AB t=0 2 4 0t=teq 2−x 4−x 2xTotal volume =1+3=4 lit[AB]=2x4=x/2[B2]=4−x4[A2]=2−x4KC=(x/2)2(4−x4)(2−x4)⇒4x2(4−x)(2−x)=4x2=(4−x)(2−x)x2=x2−6x+86x=8x=4/3concentration of AB is x/2=2/3=0.66 MHence, the correct option is B.

The gas $A_{2}$ in the left flask allowed to react with gas $B_{2}$ present in right flask at $A_{2} (g) + B_{2} (g) ⇌ 2 A B (g), K_{C} = 4$ at $27^{\circ} C$ . What is the concentration of $A B$ when equilibrium is established?