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Standard XII

Chemistry

Reaction Quotient

The gas A 2...

Question

The gas $A_{2}$ in the left flask allowed to react with gas $B_{2}$ present in the right flask as $A_{2} (g) + B_{2} (g) ⇌ 2 A B (g); K_{c} = 4$ at $27^{o} C$ . What is the concentration of $A B$ when equilibrium is established?

1.33 M

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2.6 M

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0.66 M

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0.33 M

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Solution

The correct option is B $0.66 M$
$A_{2} (g) + B_{2} (g) ⇌ 2 A B (g); K_{c} = 4$
Initial: 2 4
at eqm: 2-x 4-x 2x

So $K_{c} = (2 x)^{2} / (2 - x) (4 - x) = 4$ and

conc. of AB at eqm. is $2 x / V = 2 x / 4 = 0.66 M$

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Similar questions

Q. The gas

A_{2}

in the left flask is allowed to react with gas

B_{2}

presence in right flask as

A_{2} (g) + B_{2} (g) ⇌ 2 A B (g); K_{c} = 4

27^{o} C

. What is the concentration of

A B

when equilibrium is established?

Q. The gas

A_{2}

in the left flask allowed to react with gas

B_{2}

present in right flask at

A_{2} (g) + B_{2} (g) ⇌ 2 A B (g), K_{C} = 4

27^{\circ} C

. What is the concentration of

A B

when equilibrium is established?

Q.
2mol of

A_{2}

gas in one flask (1 lit volume) is allowed to react with 4 mol of

B_{2}

gas presence in another flask (3 lit volume) as

A_{2} (g) + B_{2} (g) ⇌ 2 A B (g); K_{c} = 4 a t 27^{o} C .

What is the concentration of AB when equilibrium is established?

Q. The gas

A_{2}

in the left flask allowed to react with gas

B_{2}

present in right flask as

A_{2} (g) + B_{2} (g) ⇌ 2 {AB(g) ; K}_{C} = 4 at 27^{\circ} C

What is the concentration of

A B

when equilibrium is established?

The gas $A_{2}$ in the left flask allowed to react with gas $B_{2}$ present in right flask as ?

$A_{2} + B_{2} ⇌ 2 A B (g); K_{c} = 4 a t 27^{\circ} C$
What is the concentration of AB when equillibrium is established-

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The gas A2 in the left flask allowed to react with gas B2 present in the right flask as A2(g)+B2(g)⇌2AB(g);Kc=4 at 27oC. What is the concentration of AB when equilibrium is established?

The correct option is B 0.66M A2(g)+B2(g)⇌2AB(g);Kc=4Initial: 2 4at eqm: 2-x 4-x 2xSo Kc=(2x)2/(2−x)(4−x)=4 and conc. of AB at eqm. is 2x/V=2x/4=0.66M

The gas $A_{2}$ in the left flask allowed to react with gas $B_{2}$ present in the right flask as $A_{2} (g) + B_{2} (g) ⇌ 2 A B (g); K_{c} = 4$ at $27^{o} C$ . What is the concentration of $A B$ when equilibrium is established?

The correct option is B $0.66 M$
$A_{2} (g) + B_{2} (g) ⇌ 2 A B (g); K_{c} = 4$
Initial: 2 4
at eqm: 2-x 4-x 2x

So $K_{c} = (2 x)^{2} / (2 - x) (4 - x) = 4$ and

conc. of AB at eqm. is $2 x / V = 2 x / 4 = 0.66 M$