The gas in a vessel in subjected to a pressure of 20 atmosphere at a temperature 27∘C. The pressure of the gas in the vessel after one half of the gas is released from the vessel and the temperature of the remainder is raised by 50∘C, is
A
8.5atm
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B
10.8atm
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C
11.7atm
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D
17atm
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Solution
The correct option is C11.7atm From ideal gas equation we get, PV=mMRT Initial conditions : P=20atmT=27+273=300K 20×V=mMR×300 Final conditions : T′=300+50=350K, m′=m2 P′×V=(m/2)MR×350 ∴P′20=3502×300 ∴P′=11.7atm.