The gases are at absolute temperature $300^{o} K$ and $350^{o} K$ respectively. The ratio of average kinetic energy of their molecules is

6 : 7

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36 : 49

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7 : 6

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343 : 216

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Solution

The correct option is A $6 : 7$
From the relation,
$¯ ¯¯¯¯¯¯¯ ¯ K E = \frac{3}{2} k T$
$\Rightarrow \frac{(¯ ¯¯¯¯¯¯¯ ¯ K E)_{1}}{(¯ ¯¯¯¯¯¯¯ ¯ K E)_{2}} = \frac{T_{1}}{T_{2}}$ (become k is constant)
Given, $T_{1} = 300 K, T_{2} = 350$ K
$∴ \frac{(K E)_{1}}{(K E)_{2}} = \frac{300}{350} = \frac{6}{7}$ .

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The gases are at absolute temperature 300oK and 350oK respectively. The ratio of average kinetic energy of their molecules is

The correct option is A 6:7From the relation,¯¯¯¯¯¯¯¯¯KE=32kT⇒(¯¯¯¯¯¯¯¯¯KE)1(¯¯¯¯¯¯¯¯¯KE)2=T1T2 (become k is constant)Given, T1=300K,T2=350K∴(KE)1(KE)2=300350=67.

The gases are at absolute temperature $300^{o} K$ and $350^{o} K$ respectively. The ratio of average kinetic energy of their molecules is