The gases hydrogen, oxygen, carbon dioxide, sulphur dioxide, and chlorine are arranged in their respective relative molecular mass. Given 8g of each gas at STP, which gas will contain the least number of the molecule and which the most?

Chlorine the least and hydrogen the most

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Chlorine the least and carbondioxide the most

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Oxygen the least and hydrogen the most

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None of these

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Solution

The correct option is B Chlorine the least and hydrogen the most

Gas

Molar Mass (in G)

Number of molecules

$H_{2}$

$O_{2}$

$C O_{2}$

$S O_{2}$

2

16+16=32

28+16=44

48

$\frac{8}{2} = 4$

$\frac{8}{32} = 0.25$

$\frac{8}{44} = 0.18$

$\frac{8}{48} = 0.167$

Number of molecules $= \frac{G i v e n M a s s}{M o l a r M a s s}$

Given mass = 8g of each gas at STP.

Example : $C l_{2} \Rightarrow$ Molar mass $= 35.5 + 35.5 = 71 g$

Number of molecules $= \frac{8 g}{71 g} = 0.1136$

Chlorine has least number of molecules and hydrogen has most nuber of molecules.

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