The GCD of $x^{2} - 2 x y + y^{2}$ and $x^{4} - y^{4}$ is

1

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x + y

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x - y

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x^{2} - y^{2}

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Solution

The correct option is C $x - y$
GCD= Greatest Common Divisor.

$x^{2} - x y - x y + y^{2}$

$= x (x - y) - y (x - y)$

$= (x - y) (x - y)$

$x^{4} - y^{4} = (x - y) (x + y) (x^{2} + y^{2})$

GCD $= x - y$

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Similar questions

(x^{2} - y^{2}) : (x^{2} + y^{2})

(x^{4} - y^{4}) : (x + y)^{4}

x, y

x + y = a, x^{2} + y^{2} = b^{2}, x^{4} + y^{4} = c^{4}

(x^{4} - y^{4}) (x^{4} + x^{2} y^{2} + y^{4}), x^{2} - y^{2}, x^{4} - y^{4}

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\frac{x^{2} - y^{2}}{x^{2} + 2 x y + y^{2}} : \frac{x - y}{x + y}

x^{2} + y^{2} = t + \frac{1}{t}

x^{4} + y^{4} = t^{2} + \frac{1}{t^{2}}

\frac{d y}{d x} = - \frac{y}{x}

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