The GCD of x4+3x3+5x2+26x+56 and x4+2x3−4x2−x+28 is x2+5x+7. Find their LCM.
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Solution
Let f(x)=x4+3x3+5x2+26x and g(x)=x4+2x3−4x2−x+28 Given that GCD =x2+5x+7. Also, we have GCD × LCM= f(x) × g(x). Thus, LCM=f(x)×g(x)GCD Now, GCD divides both f(x) and g(x). Let us divided f(X) by the GCD. When f(x) is divided by GCD, we get the quoteint as x2−2x+8. Now, (1) → LCM =(x2−2x+8)×g(x) Thus, LCM =(x2−2x+8)(x4+2x3−4x2−x+28).