The general electronic configuration of f-block elements is:

(n - 2) f^{1 - 14} (n - 1) d^{0 - 1} {n s}^{2}

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(n - 2) f^{1 - 14} (n - 1) d^{0 - 10} {n s}^{1}

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(n - 2) f^{1 - 10} (n - 1) d^{0 - 1} {n s}^{2}

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(n - 2) f^{1 - 14} (n - 1) d^{0 - 1} {n s}^{1}

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Solution

The correct option is A $(n - 2) f^{1 - 14} (n - 1) d^{0 - 1} {n s}^{2}$
The general electronic configuration of f-block elements is
$(n - 2) f^{1 - 14} (n - 1) d^{0 - 1} {n s}^{2}$

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Similar questions

(n - 2) f^{1 - 14} (n - 1) d^{0 - 1} n s^{2}

(n - 2) f^{1 - 14} (n - 1) d^{0 - 1} n s^{2}

(n - 2) f^{1 - 14} (n - 1) d^{0 - 2} n s^{2}

n s^{2} (n - 1) d^{0 - 1} (n - 2) f^{1 - 14}

(n - 1) = 6

(n - 2) f^{1 - 14} (n - 1) d^{01} n s^{2}

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