The general solution of $2 cos x - 1 = 0$ is

n π + \frac{π}{3}

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2 n π + \frac{π}{3}

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2 n π \pm \frac{π}{3}

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n π - \frac{π}{3}

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Solution

The correct option is C $2 n π \pm \frac{π}{3}$
Given $2 cos x - 1 = 0$
$⟹ 2 cos x = 1$
$⟹ cos x = \frac{1}{2}$
$⟹ cos x = cos \frac{π}{3}$
$⟹ x = 2 n π \pm \frac{π}{3}$

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