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Question

The general solution of a differential equation is y=kex. The particular solution of the equation if the curve passes through (0,1) is .

A
y=kex
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B
y=ex
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C
y=2ex
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D
y=ex+1
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Solution

The correct option is B y=ex
The curve passes through (0,1). So we will substitute the point (0,1) in the given equation y=kex.
1=k.1
k=1
So the particular solution is y=ex

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