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Question

The general solution of tan2xtanx1+tanxtan2x=1 is

A
nπ+π4,nZ
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B
nπ±π4,nZ
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C
ϕ
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D
nπ+π6,nZ
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Solution

The correct option is A nπ+π4,nZ
Formula:tan(AB)=tanAtanB1+tanAtanB

tan2xtanx1+tanxtan2x=tan(2xx)

tanx=1

xnπ+π4, nz.

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