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Question

The general solution of differential equation dydx+y sec x=tan x(0<x<π2) is


A

y(sec x + tan x) = sec x + tan x - x + c

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B

y(sec x - tan x) = sec x + tan x + x + c

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C

y(sec x - tan x) = sec x - tan x - x + c

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D

y(sec x + tan x) = sec x - tan x - x + c

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Solution

The correct option is A

y(sec x + tan x) = sec x + tan x - x + c


I.F = (secx + tanx)

G.S is y(secx + tanx) = secx + tanx – x + C


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