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Byju's Answer
Standard XII
Mathematics
General Solution of Trigonometric Equation
The general s...
Question
The general solution of
sin
θ
=
0
is
A
(
n
+
1
2
)
π
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B
n
π
+
(
−
1
)
n
π
2
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C
n
π
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D
none
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Solution
The correct option is
C
n
π
sin
θ
=
0
when
θ
=
π
,
2
π
,
3
π
,
4
π
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
Therefore, General Solution of
s
i
n
θ
=
0
is
n
π
Suggest Corrections
0
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