wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The general solution of sinθ=0 is

A
(n+12)π
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
nπ+(1)nπ2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
nπ
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
none
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C nπ
sinθ=0 when θ=π,2π,3π,4π...............

Therefore, General Solution of sinθ=0 is nπ

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
General Solutions
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon