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Question

The general solution of sin x -3 sin 2x +sin 3x =cos x -3 cos 2x +cos 3x is

A
nπ+π8
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B
nπ2+π8
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C
(1)nnπ2+π8
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D
2nπ+cos1(34)
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Solution

The correct option is B nπ2+π8

2 sin 2x cos x – 3 sin 2x = 2 cos 2x cos x – 3 cos 2x
sin2x=cos 2x Tan2x=1


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