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Question

The general solution of sinxcosx=2, for any integer n is

A
nπ
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B
2nπ+3π4
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C
2nπ
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D
(2n+1)π
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Solution

The correct option is B 2nπ+3π4
Given that, sinxcosx=2
12sinx12cosx=1
sin45sinxcos45cosx=1
cos(x+π4)=1
cos(x+π4)=cos(π)
x+π4=2nπ+π
x=2nπ+3π4

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