Question

The general solution of $\sqrt{3}\tan \theta -1=0$ is :

Answer 1

The given equation is $\sqrt{3}\tan \theta -1=0$
$\Rightarrow \tan \theta =\frac{1}{\sqrt{3}}$
We know that,
$\tan \theta =\tan \alpha \Rightarrow \theta =n\pi +\alpha ;n\in Z$
We also know that $\tan \frac{\pi }{6}=\frac{1}{\sqrt{3}}$
$\Rightarrow \tan \theta =\tan \frac{\pi }{6}$
$\Rightarrow \theta =n\pi +\frac{\pi }{6};n\in Z$