wiz-icon
MyQuestionIcon
MyQuestionIcon
4
You visited us 4 times! Enjoying our articles? Unlock Full Access!
Question

The general solution of sin x=sin α, α ϵ [π2,π2] is


A

x=nπ+(1)nα, n ϵ Z

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B

x=nπ+α, n ϵ Z

No worries! We‘ve got your back. Try BYJU‘S free classes today!
C

x=2nπ±α, n ϵ Z

No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

None of these

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A

x=nπ+(1)nα, n ϵ Z


The general solution of sin x=sin α, α ϵ [π2,π2] is
x=nπ+(1)nα, n ϵ Z


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Solving Trigonometric Equations
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon