wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The general solution of the differential equation dydx+2xy=y is (where c is a constant of integration)

A
|y|=cexx2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
y=cex2x
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
y=ce|x|
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
|y|=cex2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A |y|=cexx2
dydx+2xy=y
dydx=y(12x)
dyy=(12x)dx
on integrating it, we get
ln|y|=xx2+c1
|y|=exx2ec1=cexx2 where c=ec1
|y|=cexx2 is the required solution.

flag
Suggest Corrections
thumbs-up
2
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon