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Question

The general solution of the differential equation dydx=1+cos2y1−cos2x is

A
tany-cotx = c (c is a constant).
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B
tan x - cot y = c (c is a constant)
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C
tan y +cot x = c (c is a constant)
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D
tan x + cot y = c (c is a constant)
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Solution

The correct option is C tan y +cot x = c (c is a constant)
dydx=1+cos2y1cos2x

dydx=2cos2y2sin2x

sec2ydy=cosec2xdx

integrating both sides,

tan y = -cot x + C

tan y + cot x = C

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