wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The general solution of the differential equation dydx+sinx+y2=sinxy2 is :

A
logetany4=2sinx2+c
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
logetany2=2sinx2+c
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
logetany4=2sinx2+c
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
logetany2=sinx2+c
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A logetany4=2sinx2+c
dydx+sinx+y2=sinxy2dydx=2cosx2siny2dy2siny2=cosx2dxdy2siny2=2sinx2dy4siny4cosy4=2sinx2sec2y4 dy4tany4=2sinx2
logetany4=2sinx2+c

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Methods of Solving First Order, First Degree Differential Equations
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon