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Question

The general solution of the differential equation dydx+1+cos2y1cos2x=0 is given by:

A
tany+cotx=c
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B
tanycotx=c
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C
tanxcoty=c
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D
tanx+cotx=c
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Solution

The correct option is A tanycotx=c
dydx+1+cos2y1cos2x=0

dydx=cos2ysin2x

dycos2y=dxsin2x

sec2ydy=csc2xdx

tany+c=cotx+C
tanycotx=c

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