The general solution of the differential equation xdydx+2y=x2 is y= .
A
x24+Cx−2
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B
x24
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C
x24+C
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D
x−24+Cx2
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Solution
The correct option is Ax24+Cx−2 xdydx+2y=x2⇒dydx+2yx=x I.F=e∫Pdx=e∫2xdx=e2logx=elogx2=x2 The solution of the differential equation is y.x2=∫x.x2dx y.x2=∫x3dxy.x2=x44+Cy=x24+Cx−2