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Question

The general solution of the differential equation xdyydx=y2dx is

A
y=xCx
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B
x=2yC+x
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C
(C+x)(2x)
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D
y=2xC+x
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E
x=yCx
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Solution

The correct option is A y=xCx
We have xdyydx=y2dx
xdydxy=y2
xdydxyy2=1
⎜ ⎜ ⎜yxdydxy2⎟ ⎟ ⎟=1
ddxxy=1
xy=x+C
y=xCx

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