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Question

The general solution of the equation sinx=32 is x=

A
2nπ±π3
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B
nπ+(-1)nπ3
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C
nπ ± π6
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Solution

The correct option is B nπ+(-1)nπ3
The general solution to the equation
sinx=sinα, where α[π2,π2] is
x=nπ+(1)nα

Here, sinx=32
sinx=sinπ3.
Also, π3[π2,π2]

Hence, the general solution of the equation is x=nπ+(1)nπ3

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